Matematika Sekolah Menengah Pertama TOLONG DIKERJAIN PAKAI JALAN YAA
ITU DIJADIIN PECAHAN BIASA
MAKASIHH​

TOLONG DIKERJAIN PAKAI JALAN YAA
ITU DIJADIIN PECAHAN BIASA
MAKASIHH​

Nomor 1.

[tex] \frac{3}{7} + (1.5 \div 2.5 )\\ \\ = \frac{3}{7} + (\frac{15}{10} \div \frac{25}{10} ) \\ \\ = \frac{3}{7} + ( \frac{3}{2} \div \frac{5}{2} ) \\ \\ = \frac{3}{7} + ( \frac{3}{2} \times \frac{2}{5} ) \\ \\ = \frac{3}{7} + ( \frac{3}{1} \times \frac{1}{5} ) \\ \\ = \frac{3}{7} + \frac{3}{5} = \frac{15 + 21}{35} = \frac{36}{35} [/tex]

Nomor 2.

[tex](2.5 \div \frac{1}{4} ) - (1 \frac{1}{5} \times 20\%) \\ \\ = ( \frac{25}{10} \times \frac{4}{1} ) - ( \frac{6}{5} \times \frac{20}{100} ) \\ \\ = ( \frac{5}{2} \times \frac{4}{1} ) - ( \frac{6}{5} \times \frac{1}{5} ) \\ \\ = \frac{20}{2} - \frac{6}{25} = \frac{10}{1} - \frac{6}{25} \\ \\ = \frac{250 - 6}{25} = \frac{244}{25} [/tex]

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Penjelasan dengan langkah-langkah:

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[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]

Nomor 1 :

[tex] \frac{3}{7} + (1.5 \div 2.5)[/tex]

[tex] = \frac{3}{7} + ( \frac{15}{10} \div \frac{25}{10} )[/tex]

[tex] = \frac{3}{7} + ( \frac{3}{2} \times \frac{2}{5} )[/tex]

[tex] = \frac{3}{7} + ( \frac{3}{1} \times \frac{1}{5} )[/tex]

[tex] = \frac{3}{7} + \frac{3}{5} [/tex]

[tex] = \frac{ 36}{35} [/tex]

Nomor 2 :

[tex](2.5 \div \frac{1}{4} ) - (1 \frac{1}{5} \times 20\%)[/tex]

[tex] = (\frac{25}{10} \times \frac{4}{1} ) - ( \frac{6}{5} \times \frac{20}{100} )[/tex]

[tex] = ( \frac{5}{2} \times \frac{4}{1} ) - ( \frac{6}{5} \times \frac{1}{5} )[/tex]

[tex] = \frac{20}{2} - \frac{6}{25} [/tex]

[tex] = \frac{10}{1} - \frac{6}{25} [/tex]

[tex] = \frac{244}{25} [/tex]

[tex] = 9 \frac{76}{25} [/tex]

[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]

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